Reincarnation: I Have Always Been Rich - Chapter 7

Yan Yuling was born into a wealthy family and was an abandoned daughter since childhood. Her stepsister took her place as the pampered daughter of the Yan family and used her as a sacrificial lamb. She only wishes to have a boring, normal life.Unfortunately, she was destined to meet a handsome and talented businessman, who is also known as a 'cut-sleeve'. Their meeting is as cliche as a dog-blood drama, signaling the intertwining of their destinies. But, under the gentleman's facade, he is someone who carries dark secrets and thirsts for revenge.As they get to know each other better, they discover each other's hidden stories that could destroy their fragile relationship and kill their budding love.Faced with so many secrets, can they truly find love from each other?

“Take me in, I’ll do anything you want me to!”

In her previous life, Lu Man is sent to prison after being framed by her step-sister and an a**hole. After being released from prison, the only thing that greets her is her mother’s tombstone. Seeing the as*hole and bit*h getting happily along together like one big family with her birth father and step-mother, she sets out to die together with the as*hole and her step-sister in fiery flames.

The moment she opens her eyes again, she finds herself back on the very day she was framed. Resolutely jumping out the window and climbing next door, she seeks refuge from the man occupying the room there. But who would have guessed that the man is the brilliant hunk she has always admired from afar in her past life?

She vows to rub her eyes clean and be more discerning of people. She wants to make everyone who owed her in the past to pay her back!

“Young Master Han, can you let me hug your other arm too?”
“Actually, I have one more, do you want it?”
“…”

The main character is reborn as a character from a game he played in his previous life. This character falls into ruin along with the villainess, spending the last of their years together. A man named Kururi Helan.